Introduction to basic probability calculations:
The basic probability calculations are very helpful to the students. Calculations are the best tool to study what you want without disturbing the time. Calculation can be more interesting and interact than books and lecturing. Probability is result of examine Probability is number of possible actions divide by total quantity of proceedings. If the event arises it represents like one, or else not occurs it must symbolize zero. Now we will see basic probability calculations.
Example problems for basic probability calculations:
Example 1:- Using basic probability calculations
In school there are 100 students available. In those students, there are 50 students are science group, 25 students are maths group and 25 students are the English group. Find the probability if,
i) Science group students are leaving first from the school.
ii) English group students are leaving second from the school.
Solution:
Given,
Total students n(S)=100
Science group students n(A)=50
Maths group students n(B)=25
English group students n(C)=25
i) Let P(A) is the event of the science group students are leaving first.
So the P(A)=`(n(A))/(n(S))`
=`50/100`
=1/2
ii)Let P(B) is the event of the English group students are leaving first.
P(B)=`(n(B))/(n(S))`
=`25/100`
=1/4.
Example 2:- Using basic probability calculations
The bag has the 60 kerchiefs. In those kerchiefs, there are 15 is the blue color, 20 is the yellow color and 25 is the white color. If John select the white color kerchief means solve the probability?
Solution:
First list the given information,
Total kerchiefs n(S)=60
Blue colour kerchiefs n(A)= 15
Yellow colour kerchiefs n(B)= 20
White colour kerchiefs n(C) = 25
Assume P(E) is the probability for john select the white colour kerchief.
So P(E)=`(n(C ))/(n(S))`
=`25/60`
=`5/12` .
In the above way we can solve the problems.
Having problem with Uniform Probability Distribution keep reading my upcoming posts, i will try to help you.
Example 3:- Using basic probability calculations
Two coins are spinning. What is the probability for if two head are receiving?
Answer
Two coins flipped means the feasible outcomes are {(H,T),(H,H),(T,H),(T,T)}
So the total numbers of outcomes are 4.
We get the two head possibility is 1.
Probability = 1/4.
Example 4:- Using basic probability calculations
From the following scores are 41,13,46,27,79,25,15. We can find the probability for above 25 scores? 2.
Solution:
Probability for finding above 25 scores:
Above 25 scores=41, 46, 27, 79.
In the given scores the above 35scores probability values are (41, 46, 27, 79)
Probability for above 25 scores=41+46+27+79
=193.
Total scores values = (41+13+46+27+79+25+15) =246.
Probability=above 25/Total given scores.
Total scores=246
Probability for above 25 scores=`193/246` .
=`193/246` .
Formulas for finding probabilities for below 25 scores are,
The basic probability calculations are very helpful to the students. Calculations are the best tool to study what you want without disturbing the time. Calculation can be more interesting and interact than books and lecturing. Probability is result of examine Probability is number of possible actions divide by total quantity of proceedings. If the event arises it represents like one, or else not occurs it must symbolize zero. Now we will see basic probability calculations.
Example problems for basic probability calculations:
Example 1:- Using basic probability calculations
In school there are 100 students available. In those students, there are 50 students are science group, 25 students are maths group and 25 students are the English group. Find the probability if,
i) Science group students are leaving first from the school.
ii) English group students are leaving second from the school.
Solution:
Given,
Total students n(S)=100
Science group students n(A)=50
Maths group students n(B)=25
English group students n(C)=25
i) Let P(A) is the event of the science group students are leaving first.
So the P(A)=`(n(A))/(n(S))`
=`50/100`
=1/2
ii)Let P(B) is the event of the English group students are leaving first.
P(B)=`(n(B))/(n(S))`
=`25/100`
=1/4.
Example 2:- Using basic probability calculations
The bag has the 60 kerchiefs. In those kerchiefs, there are 15 is the blue color, 20 is the yellow color and 25 is the white color. If John select the white color kerchief means solve the probability?
Solution:
First list the given information,
Total kerchiefs n(S)=60
Blue colour kerchiefs n(A)= 15
Yellow colour kerchiefs n(B)= 20
White colour kerchiefs n(C) = 25
Assume P(E) is the probability for john select the white colour kerchief.
So P(E)=`(n(C ))/(n(S))`
=`25/60`
=`5/12` .
In the above way we can solve the problems.
Having problem with Uniform Probability Distribution keep reading my upcoming posts, i will try to help you.
Example 3:- Using basic probability calculations
Two coins are spinning. What is the probability for if two head are receiving?
Answer
Two coins flipped means the feasible outcomes are {(H,T),(H,H),(T,H),(T,T)}
So the total numbers of outcomes are 4.
We get the two head possibility is 1.
Probability = 1/4.
Example 4:- Using basic probability calculations
From the following scores are 41,13,46,27,79,25,15. We can find the probability for above 25 scores? 2.
Solution:
Probability for finding above 25 scores:
Above 25 scores=41, 46, 27, 79.
In the given scores the above 35scores probability values are (41, 46, 27, 79)
Probability for above 25 scores=41+46+27+79
=193.
Total scores values = (41+13+46+27+79+25+15) =246.
Probability=above 25/Total given scores.
Total scores=246
Probability for above 25 scores=`193/246` .
=`193/246` .
Formulas for finding probabilities for below 25 scores are,