Showing posts with label algebraic expressions. Show all posts
Showing posts with label algebraic expressions. Show all posts

Sunday, March 31

Approaches to Problem Solving


Introduction to approaches to problem solving:-

In this article we are going to see the important approaches to problem solving. Algebra is a cluster of math, we use script like a, b, x and y to denote numbers. In Algebra we execute count, division, increase, allotment, extraction of roots and substituting. Variables and numbers used as real numbers, algebra is unique, importance and computational skills we obtain what are called algebraic expressions.

Simple approaches to solving- Example problems:-

Approaches to solving- Example problem1:-

Solve - 2 (x + 3) = - 10

Solution:-

Solving algebraic equation

- 2 (x + 3) = - 10

-2x – 6 = -10

-2x = - 10 + 6

-2x = - 4

x = 2.

Approaches to solving- Example problem2:-

5 ( x + 2 ) + 3 ( x – 2 ) = 10

Solution:-

Solving algebraic equations

5 ( x + 2 ) + 3 ( x – 2 ) = 10

5x + 10 + 3x – 6 = 10

5x – 3x + 10 - 6 = 10

2x + 4 = 10

2x = 10 – 4

2x = 6

x = 6/2

x = 3.

Approaches to solving- Example problem3:-

-2( x + 4 ) + 3 ( x + 2 ) = 4x + 20

Solution:-

Solving algebraic equation

-2( x + 4 ) + 3 ( x + 2 ) = 4x + 20

-2x – 8 + 3x + 6 = 4x + 20

-2x + 3x - 8 + 6 = 4x + 20

x - 2 = 4x + 20

x - 4x = 2 0+ 2

- 3x = 22

x = -22/3.

Understanding Inch to Feet is always challenging for me but thanks to all math help websites to help me out.

Approaches to solving- practice problems:-

Problem 1:-

Solve 3x -2(2x - 5) = 2 (x + 3) - 8

Answer:-

x=4.

Problem 2:-

3 (x - 3) = 5(2x+1)

Answer:-2.

Problem 3:-

Solve 15 (m - 4) - 2 (m - 9) + 5 (m + 6) =0

Answer:-

2/3.