Showing posts with label algebra problems. Show all posts
Showing posts with label algebra problems. Show all posts

Wednesday, March 27

Math Children Computer


Introduction to math children computer:

Math children computer is the help through computer to the children in math. Chidren when they solve math homework problems they come across lot of difficulties as the online tutoring websites help children in solving their problems. Tuotr vista is one of the best online tutoring website that help in math shildren in online through computer. Here in this article let us see sample problems solved from tutorvista  for math children computer.

Looking out for more help on Polynomial Equations in algebra by visiting listed websites.

Math children computer:


Basic algebra problems:

Example 1 :
What is the sum of 7 and 8? Express this statement by using place holder.
Solution :

We can write this statement, in short, as
7 + 8 = ?.

The answer for this problem would be 7 + 8 = 15.

Example 2 :
What number added to 10 will give 15?
Solution :
It is 10 + x = 15

Example 3 :
Rabi has 18 rupees. She buys vegetables for 8 rupees. Find the remaining amount she will have in her hands.
Solution :
We can write it as 18 – 8 = ?

The answer for this problem would be 18 - 8 = 10.

Example 4 :
Find the product of 5 and 12
Solution :
5 × 12 =?

The answer for this problem would be 5 × 12 = 60.

Example 5 :
When a number is multiplied by 4, the product is 116
Solution :
x × 4 = 116.

x = `116 / 4` = 29.

I have recently faced lot of problem while learning Logarithm Calculator, But thank to online resources of math which helped me to learn myself easily on net.

Math children computer:


Example 6:
What is the sum of 9 and 10? Express this statement by using place holder.
Solution:

We can write this statement, in short, as
9 + 10 = ?.

The answer for this problem would be 9 + 10 = 19.

Example 7:
What number added to 12 will give 17?
Solution:
It is 12 + x = 17
The answer would be x = 17 - 12 = 5.

Example 8:
Rabi has 28 rupees. She buys vegetables for 12 rupees. Find the remaining amount she will have in her hands.
Solution:
We can write it as 28 – 12 = ?

The answer for this problem would be 28 - 12 = 16.

Example 9:
Find the product of 6 and 12
Solution:
6 × 12 =?

The answer for this problem would be 6 × 12 = 72.

Example 10:
When a number is multiplied by 4, the product is 84
Solution:
x × 4 = 84.

x = `84 / 4` = 21.

Monday, February 25

Fun Algebra Problems


Introduction:

Fun Algebra problem, the algebraic expressions are shaped as of variables and constants. We employ the Operations of addition, subtraction, multiplication and division on the variable sand constants to form expressions. Expressions are group of terms. Terms be added to make an expression. A term is a creation of factors. The coefficient is the arithmetic factor in the term. Sometimes everyone factor in a term is called the coefficient of the remaining part of the term.

Solution of an Equation

Algebra does not take in real numbers, matrices, complex numbers vectors etc, the algebraic function look like x + y = y + x

Fun Algebra Problem Example 1:

We state y = 3 is the  answer to the equation 5 × y + 4 = 19, in favor of replacing each incidence of y with 3 gives us

5× 3 + 4 = 19  ==>

15 + 4 = 19  ==>

19 = 19 which is true.

Fun Algebra Problem Example 2 :

x = 100 is a result to the equation x ÷ 2 - 40 = 10

z = 18 is a result to the equation 5 × (z - 6) = 60

Fun Algebra Problem Counterexample:

y = 10 is NOT a result to the equation 5 × y + 4 = 19. While we replace every y with 10, we get

5 × 10 + 4 = 19  ==>

50 + 4 = 19  ==>

54 = 19 not true!

I have recently faced lot of problem while learning Reciprocal Function Graph, But thank to online resources of math which helped me to learn myself easily on net.

Algebraic expression Example:

Fun Algebra Problem

This problem illustrates alliance like terms and dealing with subtraction in an algebraic equation.

Solve x - 10 + 18 = 35.

Replacing the -10 with a + (-10), we get

x + (-10) + 18 = 35.

Since addition is associative, the two like situation (the integers) may be combined.

(10) + 18 = 8

The left side of the equation becomes

x + 8 = 35.

At present we may subtract 8 from each side of the equation, (we will in fact add a -8 to each part).

x + 8 + (-8) = 35 + (-8)

x + 0 = 27

x = 27

We can check this solution in the original given algebraic equation:

27 - 10 + 18 = 35x + 0 = 27

17 + 18 = 35

35 = 35 so our solution is correct.