Introduction of Basic Algebra For:
Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics. The part of algebra called elementary algebra.
Source – Wikipedia.
Basic Algebra for Addition and Subtraction:
The followings are some of the examples for basic algebra of addition and subtraction.
Addition of fractions: `4/9 ` +` 4/9` .
Solution:
From the fraction denominators are same.
By adding the numerator and same as in the denominator:
= `4/9` +` 4/9`
=` (4 +4)/9`
=` 8/9`
By Simplify and adding the fraction:
= `8/9`
= `4/3`
Subtraction of fractions: ` 2/6` - `4/6` .
Solution:
From the fraction denominators are same.
By subtract the numerator and same as in the denominator:
= `2/6 ` - `4/6`
= `(2- 4)/ 6`
=` -2/6`
By Simplify and subtract the fraction:
=` -2/6`
= `-1/3`
Algebraic expression of addition: 10x + 7y + 3x + 5a.
Solution:
The given expressions are 10x + 7y + 3x + 5a
The like terms in expression are 10x and -3x. We cannot do anything the 7y or 5a.
Then group the terms and add.
= (10x + 3x) + 5a + 7y
= 5a + 13x + 7y
I have recently faced lot of problem while learning Compound Interest Equation, But thank to online resources of math which helped me to learn myself easily on net.
Basic Algebra for Multiplication and Division:
The followings are some of the examples for basic algebra of multiplication and division.
Multiply the integers: 5 × 9.
Solution:
Given integers are (5) × (9)
= |5| × |9|
= 5 × 9
= 45 is the solution for the given integers.
Multiply the integers: 4 × (-5).
Solution:
Given integers are 4 × (-5)
= 4 × -5
= 4 × -5
= -20 is the solution for the given integers.
Divide: 8a^2 – 40 by 8
Solution:
The given polynomials are 8a^2 – 40 ÷ 8
= `(8a^2-40)/8`
By dividing them we get
= `(8a^2)/ 8` * `-40/8`
= a^2 - 5
Divide: 12a^2 – 24 by 4
Solution:
The given polynomials are 12a^2 – 24 ÷ 4
= `(12a^2-24)/4`
By dividing them we get
= `(12a^2)/4` *` -24/4`
= 3a^2 - 6
Algebra is the branch of mathematics concerning the study of the rules of operations and relations, and the constructions and concepts arising from them, including terms, polynomials, equations and algebraic structures. Together with geometry, analysis, topology, combinatorics, and number theory, algebra is one of the main branches of pure mathematics. The part of algebra called elementary algebra.
Source – Wikipedia.
Basic Algebra for Addition and Subtraction:
The followings are some of the examples for basic algebra of addition and subtraction.
Addition of fractions: `4/9 ` +` 4/9` .
Solution:
From the fraction denominators are same.
By adding the numerator and same as in the denominator:
= `4/9` +` 4/9`
=` (4 +4)/9`
=` 8/9`
By Simplify and adding the fraction:
= `8/9`
= `4/3`
Subtraction of fractions: ` 2/6` - `4/6` .
Solution:
From the fraction denominators are same.
By subtract the numerator and same as in the denominator:
= `2/6 ` - `4/6`
= `(2- 4)/ 6`
=` -2/6`
By Simplify and subtract the fraction:
=` -2/6`
= `-1/3`
Algebraic expression of addition: 10x + 7y + 3x + 5a.
Solution:
The given expressions are 10x + 7y + 3x + 5a
The like terms in expression are 10x and -3x. We cannot do anything the 7y or 5a.
Then group the terms and add.
= (10x + 3x) + 5a + 7y
= 5a + 13x + 7y
I have recently faced lot of problem while learning Compound Interest Equation, But thank to online resources of math which helped me to learn myself easily on net.
Basic Algebra for Multiplication and Division:
The followings are some of the examples for basic algebra of multiplication and division.
Multiply the integers: 5 × 9.
Solution:
Given integers are (5) × (9)
= |5| × |9|
= 5 × 9
= 45 is the solution for the given integers.
Multiply the integers: 4 × (-5).
Solution:
Given integers are 4 × (-5)
= 4 × -5
= 4 × -5
= -20 is the solution for the given integers.
Divide: 8a^2 – 40 by 8
Solution:
The given polynomials are 8a^2 – 40 ÷ 8
= `(8a^2-40)/8`
By dividing them we get
= `(8a^2)/ 8` * `-40/8`
= a^2 - 5
Divide: 12a^2 – 24 by 4
Solution:
The given polynomials are 12a^2 – 24 ÷ 4
= `(12a^2-24)/4`
By dividing them we get
= `(12a^2)/4` *` -24/4`
= 3a^2 - 6
