Introduction to the substitution method solver:-
In algebra, a linear system of two equations can be solved by two methods. (1) Elimination method (2) substitution method.
If one equation is of the form ax + by +c = 0 and the other equation is of the form px + qy + d = 0 then we can use the substitution
methods by substituting x for y or y for x and solve the equations.
Step 1 : Take the equation ax + by = -c
ax = -by - c
x = -by - c
a a
Step 2 : Substitute the value of x in the second equation px + qy +d=0 and find y.
Step 3 : Substitute the value of y in any one of the two given equation and solve for x
Alternatively you can substitute the value of y in the step 1 equation also to find x
This is called substitution method solver.
Solve Example by Substitution Methods:-
Here is a problem of linear equation which we are going to solve by substitution methods.
# Solve 2x + 3y = 8 and 5x + 2y = 9
Solution:-
Step 1 : Let us write the first equation 2x + 3y = 8
2x = 8 - 3y
x = ( 8 - 3y)/2
Step 2 : Let us substitute the x value in the equation 5x + 2y = 9
5( 8 - 3y)/2 + 2y = 9
( 40 - 15y)/2 + 2y = 9
20 - 7.5 y + 2y = 9
20 - 5.5y = 9
Step 3 : Let us subtract 20 from both sides - 20 - 20
______________________
- 5.5 y = - 11
Step 4 : Let us divide both sides by 5.5 we get -y = -2
Step 5 : Cancelling negative sign on both sides we get y = 2
Step 6 : Substituting the value of y = 2 for x = (8 - 3y) /2 we get (8 - 3*2) / 2
= ( 8 - 6)/2
= 2/2
= 1
Answer : x = 1 and y = 2
Step 7 : Let us check our solution by substituting x = 1 and y = 2 in any one of the equation given in the problem
Let us check on 2x + 3y = 8
2(1) + 3(2) gives 2 + 6 = 8 which is the RHS
Hence our solution is correct.
Solving Problem on a Linear Equation by Substitution Method:-
Let us do another linear equation problem by substitution method:
# Solve 3x + 2y = 7/4 and 2x + 3y = 2
Solution:
Step 1 : Let us use the first equation to find the value of y
3x + 2y = 7/4
2y = 7/4 - 3x
y = 7/8 - 3x/2
Step 2 : Let us substitute the y value in the equation 2x + 3y = 2
2x + 3( 7 - 3x) = 2
8 2
2x + 21 - 9x = 2
8 2
2x - 4.5x = 2 - 21
8
- 2.5x = 16 - 21
8
- 2.5x = -5/8
- 2.5x = - 0.625
Step 3 : Let us divide both sides by 2.5 we get -x = - 0.25
x = 0.25
x = ¼
Step 4 : Let us substitute x = 1/4 in equation y = 7 - 3x
8 2
y = 7 - 3*¼
8 2
y = 7 - 3
8 8
y = 4/8
y = ½
Answer : The solution for this problem is x = ¼ and y = ½
Let us check our solution to see if it is correct
Step 1 : substituting x = ¼ and y = ½ in one of the equations say 2x + 3y we get 2*¼ + 3 *½ = 1 + 3 = 2 RHS
2 2
Hence our solution is correct.
In algebra, a linear system of two equations can be solved by two methods. (1) Elimination method (2) substitution method.
If one equation is of the form ax + by +c = 0 and the other equation is of the form px + qy + d = 0 then we can use the substitution
methods by substituting x for y or y for x and solve the equations.
Step 1 : Take the equation ax + by = -c
ax = -by - c
x = -by - c
a a
Step 2 : Substitute the value of x in the second equation px + qy +d=0 and find y.
Step 3 : Substitute the value of y in any one of the two given equation and solve for x
Alternatively you can substitute the value of y in the step 1 equation also to find x
This is called substitution method solver.
Solve Example by Substitution Methods:-
Here is a problem of linear equation which we are going to solve by substitution methods.
# Solve 2x + 3y = 8 and 5x + 2y = 9
Solution:-
Step 1 : Let us write the first equation 2x + 3y = 8
2x = 8 - 3y
x = ( 8 - 3y)/2
Step 2 : Let us substitute the x value in the equation 5x + 2y = 9
5( 8 - 3y)/2 + 2y = 9
( 40 - 15y)/2 + 2y = 9
20 - 7.5 y + 2y = 9
20 - 5.5y = 9
Step 3 : Let us subtract 20 from both sides - 20 - 20
______________________
- 5.5 y = - 11
Step 4 : Let us divide both sides by 5.5 we get -y = -2
Step 5 : Cancelling negative sign on both sides we get y = 2
Step 6 : Substituting the value of y = 2 for x = (8 - 3y) /2 we get (8 - 3*2) / 2
= ( 8 - 6)/2
= 2/2
= 1
Answer : x = 1 and y = 2
Step 7 : Let us check our solution by substituting x = 1 and y = 2 in any one of the equation given in the problem
Let us check on 2x + 3y = 8
2(1) + 3(2) gives 2 + 6 = 8 which is the RHS
Hence our solution is correct.
Solving Problem on a Linear Equation by Substitution Method:-
Let us do another linear equation problem by substitution method:
# Solve 3x + 2y = 7/4 and 2x + 3y = 2
Solution:
Step 1 : Let us use the first equation to find the value of y
3x + 2y = 7/4
2y = 7/4 - 3x
y = 7/8 - 3x/2
Step 2 : Let us substitute the y value in the equation 2x + 3y = 2
2x + 3( 7 - 3x) = 2
8 2
2x + 21 - 9x = 2
8 2
2x - 4.5x = 2 - 21
8
- 2.5x = 16 - 21
8
- 2.5x = -5/8
- 2.5x = - 0.625
Step 3 : Let us divide both sides by 2.5 we get -x = - 0.25
x = 0.25
x = ¼
Step 4 : Let us substitute x = 1/4 in equation y = 7 - 3x
8 2
y = 7 - 3*¼
8 2
y = 7 - 3
8 8
y = 4/8
y = ½
Answer : The solution for this problem is x = ¼ and y = ½
Let us check our solution to see if it is correct
Step 1 : substituting x = ¼ and y = ½ in one of the equations say 2x + 3y we get 2*¼ + 3 *½ = 1 + 3 = 2 RHS
2 2
Hence our solution is correct.