Problem Solving Fifth Grade

Introduction to fifth grade math:

In the level of fifth grade the students will learn about decimals, fraction, and addition using decimal numbers, subtraction using decimal numbers, multiplication and division using decimal numbers. Basic operation of area, circle, volume, and perimeter will be come under the level of fifth graders math. In this article the students solving problems from fifth grade. I like to share this Roman Numeral Calculator with you all through my article.

Solving Fifth Grade Problems:

Problem 1:

Solving the given problem:

The length of the rectangular slab is 150 cm and the breadth of the rectangular slab is 50 cm. find the perimeter of the rectangular slab.

Solution:

Length of the rectangular slab = 150 cm.

Breadth of the rectangular slab = 50cm

Hence, the perimeter of the rectangular slab is given by

Perimeter P = 2 x (l + b)

= 2 x (150 + 50) cm

= 2 x 200 cm

= 400 cm.

Problem 2:

Solving the given problem

David purchased a wooden box. It is square shape and its side is 4 m. find the perimeter of the wooden box.

Solution:

Side of the square = 4 m.

The perimeter of the wooden box is given by,

Perimeter P = 4 x side

= 4 x 4m

= 16 m

The perimeter of the wooden box = 16 m. Understanding math online help for free is always challenging for me but thanks to all math help websites to help me out.

Solving Fifth Grade Problems:

Problem 3:

Solving the given problem

Find the area of the given rectangle. The length and breadth of the rectangle is 10 cm and 5 cm respectively.

Solution:

Length of the rectangle = 10cm

Breadth of the rectangle = 5 cm

Area of the rectangle = l x b

= 10 x 5 sq cm

= 50 sq cm.

Problem 4:

The length of the cuboid is 7 cm, breadth of the cuboid is 3.5 cm, and the height of the cuboid is 4 cm. find the cuboid volume.

Solution:

Length of the cuboid = 7cm

Breadth of the cuboid = 3.5 cm

Height of the cuboid = 4 cm

Volume of the cuboid = l x b x h

= 7 x 3.5 x 4 cu cm.

= 98 cu cm.

Problem 5:

Find the volume of the cubical container. Its side is 3.4 cm.

Solution:

Side length of the cube = 3.4 cm.

Volume of the cube = l x l x l

= 3.4 x 3.4 x 3.4 cu cm

= 39.304 cu cm.

Equivalent Fractions Number Line

Introduction to equivalent fractions number line:

Fractions:

A fraction is a number that can represent part of a whole. The earliest fractions were reciprocals of integers: ancient symbols representing one part of two, one part of three, one part of four, and so on. A much later development was the common or "vulgar" fractions which are still used today (½, ?, ¾, etc.) and which consist of a numerator and a denominator.

Equivalent fractions:

Two or more fractions has the same value is known as equivalent fractions.

In this article we are going to see about equivalent fractions number line and  some problems based on equivalent fractions number line.

Equivalent Fractions Number Line :

The equivalent fractions number line used to show the equivalent fractions in chart. The following figure shows the equivalent fractions number line.

Fig(i) Equivalent fractions number line

The above figure shows the equivalent fraction number line for 1/8 .

By using this number line, we get equivalent fractions of 1/8 is 2/16. Let us see some problems on finding equivalent fractions .

Between, if you have problem on these topics how to multiply 3 fractions, please browse expert math related websites for more help on how to divide and multiply fractions.

Problems Equivalent Fractions Number Line :

Problem 1:

Find 2 equivalent fractions to 3/5

Solution:

Given , fraction 3/5

We need to find the equivalent fraction to `3/5`

Multiply 3/5 by 2 on both numerator and denominator,

`3/5` = `( 3 * 2 ) / (5 * 2)`

= `6/ 10`

Equivalent fraction to `3/5 ` = `6 / 10` .

Multiply `3/5` by 5 on both numerator and denominator,

`3/5` = `( 3 * 5) / ( 5 * 5 )`

= `15/ 25`

Equivalent fraction to `3/5` = `6 /10` = `15 /25`

Answer: 2 equivalent fractions of `3 / 5` is `6/ 10` , `15 /25`

Problem 2:

Find the 3 equivalent fractions of `2/15` .

Solution:

Given, The fraction `2/15` .

We need to find the equivalent fraction to `2/15`

Multiply `2/15` by 2 on both numerator and denominator,

`2/15` = `( 2 * 2 ) / (15 * 2)`

= `4/ 30`

Equivalent fraction to `2/15 ` = `4 / 30` .

Multiply  2/15 by 5 on both numerator and denominator,

`2/15 ` = `( 2*5) / ( 15*5 )`

= ` 10/ 75`

Equivalent fraction to `2/15` = `4 / 30` = `10/75`

Multiply ` 2/15` by 3 on both numerator and denominator,

`2/15` = `( 2* 3 ) / (15 * 3)`

= `6/ 45`

Answer: 3 equivalent fraction of `2/ 15` is `4/ 30` , `10/ 75` , `6 /45`

Problem 3:

Find the 3 equivalent fractions of `8/12` .

Solution:

Given, The fraction `8/12` .

We need to find the equivalent fraction to `8/12`

Multiply `8/12` by 2 on both numerator and denominator,

`8/12` = `( 8 * 2 ) / (12 * 2)`

= `16/ 24`

Equivalent fraction to `8/12 ` = `16 / 24` .

Multiply  8/12 by 5 on both numerator and denominator,

`8/12 ` = `( 8*5) / ( 12*5 )`

= ` 40/ 60`

Equivalen fraction to `8/12` = `16 / 24` = `40/60`

For another equivalent fraction, Multiply ` 8/12` by 3 on both numerator and denominator,

`8/12` = `( 8* 3 ) / (12 * 3)`

= `24/ 36`

Answer: 3 equivalent fraction of `8/ 12` is `16/ 24` , `40/ 60` , `24 /36`