Monday, January 7

Probability Grade


Probability Introduction:
The probability is number of possible events divided into total number of possible events. Probability contains two types of distributions. These are the discrete and continuous distribution.  The general formation of the grade 3 probability

The probability event P (A) = `("No. of possible events n(a)")/("Total no. of events n(s)")`

Examples on Probability Grade 3

Dice Problems:

Grade 3 Probability Example 1:

Roll a single dice; find the probability of get number 6.

Sol:

Total Number of possible = n (a) = {1, 2, 3, 4, 5, 6}

n (s) = 6

The number of outcomes n (a) = {6}

n (a) = 1

The probability of getting value = `1/6` = 0167.

Grade 3 Probability Example 2:

Roll a single dice; find the probability of get number 1.

Sol:

Total Number of possible = n (a) = {1, 2, 3, 4, 5, 6}

n (s) = 6

The number of outcomes n (a) = {6}

n (a) = 1

The probability of getting value = `1/6` .

Grade 3 Probability Example 3:

Roll a single dice; find the probability of get number 5.

Sol:

Total Number of possible = n (a) = {1, 2, 3, 4, 5, 6}

n (s) = 6

The number of outcomes n (a) = {5}

n (a) = 1

The probability of getting value = `1/6` = 0.167.

Grade 3 Probability Example 4:

Roll a single dice; find the probability of get number 4.

Sol:

Total Number of possible = n (a) = {1, 2, 3, 4, 5, 6}

n (s) = 6

The number of outcomes n (a) = {4}

n (a) = 1

The probability of getting value = `1/6` . Please express your views of this topic what is differentiation by commenting on blog.

Coins Problems on Probability Grade 3

Grade 3 Probability Example 5:
To toss a coin and find the probability of one head. The possible outcomes are:

Sol:

Step 1:

n (s) = {T, H} = 2

Step 2:

Tossing a coin with only one head:

n (a) = {H}=1

Step 3:

Formula:

P (A) = `(n(a))/(n(s))`

Answer:

P (A) = `1/2` .

Convert into a decimal 0.5

The probability of one head is 0.5 or Rounded 50%.

Grade 3 Probability Example 6:
Toss a coin and find the probability of one tail. The possible outcomes are:

Solution:

Step 1:

n (s) = {T, H}=2

Step 2:

Tossing a coin with only one tail:

n (a) = {T}=1

Step 3:

Formula:

P (A) = `(n(a))/(n(s))`

Answer:

P (A) = `1/2` .

Convert into a decimal 0.5

The probability of one tail is 0.5 or Rounded 50%.

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